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For a first order reaction, a graph of log([R]/(mol/L))… | StemPy Lab
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For a first order reaction, a graph of log([R]/(mol/L)) against time is a straight line with a slope of -0.0120 min⁻¹. What is the half-life?
Chemistry
Medium
High School (11–12)
Chemical Kinetics › Integrated Rate Equations and Half-Life
AP
A-Level
IB
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StemPy Lab
For a first order reaction, a graph of
log
(
[
R
]
/
(
mol/L
)
)
\log([R]/(\text{mol/L}))
lo
g
([
R
]
/
(
mol/L
))
against time is a straight line with a slope of
−
0.0120
min
−
1
-0.0120\ \text{min}^{-1}
−
0.0120
min
−
1
. What is the half-life?
133
min
133\ \text{min}
133
min
57.8
min
57.8\ \text{min}
57.8
min
50.2
min
50.2\ \text{min}
50.2
min
25.1
min
25.1\ \text{min}
25.1
min
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← A first order reaction is 60 % complete in 20 min. How long does it take to be 90 % complete? Take log 2 = 0.301.
Which of these statements are correct? (i) The unit of k for a first order reaction stays the same when the concentration is measured in bar instead of mol/L. (ii) The half-life of a zero order reaction doubles when the start concentration doubles. (iii) A first order reaction is about 94 % complete after four half-lives. (iv) For a zero order reaction a graph of ln[R] against time is a straight line. →
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Chemical Kinetics › Integrated Rate Equations and Half-Life
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