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For -1 < x < 1 the function sin⁻¹x has no obvious… | StemPy Lab

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For -1 < x < 1 the function sin⁻¹x has no obvious product in it. Treating it as sin⁻¹x · 1, which is its antiderivative, apart from the constant?

MathematicsHardHigh School (11–12)Functions and Calculus › Integrals A-Level AEEE (Amrita)AMUEEE AP AP EAPCET BCECE COMEDK UGET CUET UG GUJCET IB JCECE JKCET KCET KEAM KIITEE LPUNEST MET (Manipal)MHT-CET OJEE SRMJEEE TS EAPCET UPESEAT VITEEE

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For $-1 < x < 1$ the function $\sin^{-1}x$ has no obvious product in it. Treating it as $\sin^{-1}x \cdot 1$ , which is its antiderivative, apart from the constant?

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← A student notices that sin x is the derivative of -cos x, and she wonders about ∫ eˣ(sin x + cos x)dx. Which result is correct?The fraction (2x² + 3)/(x² - 1) has top and bottom of the same degree. After dividing, the integral is found by partial fractions. What is the antiderivative on x > 1, apart from the constant? →

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