Find the sum 2⋅12+3⋅22+4⋅32+⋯+21⋅2022 \cdot 1^2 + 3 \cdot 2^2 + 4 \cdot 3^2 + \dots + 21 \cdot 20^22⋅12+3⋅22+4⋅32+⋯+21⋅202, where the kkkth term is (k+1)k2(k + 1)k^2(k+1)k2. You may use the standard formulas for ∑k2\sum k^2∑k2 and ∑k3\sum k^3∑k3.
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