Calcium carbonate has $K_{sp} = 3.3 \times 10^{-9}$. Hard water has $[\text{Ca}^{2+}] = 2.0 \times 10^{-4}\ \text{mol/L}$ and $[\text{CO}_3^{2-}] = 3.0 \times 10^{-5}\ \text{mol/L}$. What happens?