How deep must a diver go before the water alone presses as hard as the whole atmosphere, 1.0×105 Pa1.0 \times 10^{5}\ \text{Pa}1.0×105 Pa? (ρ=1000 kg/m3\rho = 1000\ \text{kg/m}^3ρ=1000 kg/m3, g=9.8 m/s2g = 9.8\ \text{m/s}^2g=9.8 m/s2)
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