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Add up ¹⁰C₀/1 + ¹⁰C₁/2 + … + ¹⁰C₁₀/11. The total is | StemPy Lab
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Add up ¹⁰C₀/1 + ¹⁰C₁/2 + … + ¹⁰C₁₀/11. The total is
Mathematics
Hard
High School (11–12)
Algebra › Binomial Theorem
JEE Main
A-Level
IB
Created by
StemPy Lab
Add up
10
C
0
1
+
10
C
1
2
+
⋯
+
10
C
10
11
\dfrac{{}^{10}C_{0}}{1} + \dfrac{{}^{10}C_{1}}{2} + \cdots + \dfrac{{}^{10}C_{10}}{11}
1
10
C
0
+
2
10
C
1
+
⋯
+
11
10
C
10
. The total is
2047
11
\dfrac{2047}{11}
11
2047
2047
10
\dfrac{2047}{10}
10
2047
2047
12
\dfrac{2047}{12}
12
2047
4095
11
\dfrac{4095}{11}
11
4095
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