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A standing wave is y = 4 sin(π x/12) cos(50π t), with y… | StemPy Lab
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A standing wave is y = 4 sin(π x/12) cos(50π t), with y in mm, x in cm and t in s. What is the amplitude of the point at x = 2 cm?
Physics
Medium
High School (11–12)
Waves & Sound › Superposition and Standing Waves
JEE Main
Created by
StemPy Lab
A standing wave is
y
=
4
sin
(
π
x
/
12
)
cos
(
50
π
t
)
y = 4\sin(\pi x/12)\cos(50\pi t)
y
=
4
sin
(
π
x
/12
)
cos
(
50
π
t
)
, with
y
y
y
in mm,
x
x
x
in cm and
t
t
t
in s. What is the amplitude of the point at
x
=
2
cm
x = 2\ \text{cm}
x
=
2
cm
?
1
mm
1\ \text{mm}
1
mm
2
mm
2\ \text{mm}
2
mm
3.46
mm
3.46\ \text{mm}
3.46
mm
4
mm
4\ \text{mm}
4
mm
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