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A silver electrode dips into silver nitrate solution at… | StemPy Lab
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A silver electrode dips into silver nitrate solution at 0.0070 mol/L at 298 K. Use E°(Ag⁺/Ag) = 0.80 V. What is the electrode potential?
Chemistry
Medium
High School (11–12)
Electrochemistry › Galvanic Cells, Electrode Potential and the Nernst Equation
Board Exam
AP
A-Level
IB
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StemPy Lab
A silver electrode dips into silver nitrate solution at
0.0070
mol/L
0.0070\ \text{mol/L}
0.0070
mol/L
at
298
K
298\ \text{K}
298
K
. Use
E
∘
(
Ag
+
/
Ag
)
=
0.80
V
E^\circ(\text{Ag}^+/\text{Ag}) = 0.80\ \text{V}
E
∘
(
Ag
+
/
Ag
)
=
0.80
V
. What is the electrode potential?
0.67
V
0.67\ \text{V}
0.67
V
0.74
V
0.74\ \text{V}
0.74
V
0.80
V
0.80\ \text{V}
0.80
V
0.93
V
0.93\ \text{V}
0.93
V
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← The cell Fe(s) mid Fe²⁺(aq) ∥ Cu²⁺(aq) mid Cu(s) has E° = 0.78 V and n = 2 at 298 K. At one moment its emf is 0.85 V. What is the reaction quotient Q at that moment?
In the cell reaction 2Al(s) + 6H⁺(aq) → 2Al³⁺(aq) + 3H₂(g), the pressure of hydrogen is doubled and nothing else changes. By what factor does the reaction quotient Q change? →
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Electrochemistry › Galvanic Cells, Electrode Potential and the Nernst Equation
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