A pendulum clock with a steel rod keeps correct time at 20 °C. How many seconds does it lose in a day at 40 °C? (α = 1.2 × 10⁻⁵ K⁻¹; T ∝ √L.)

PhysicsHardHigh School (11–12)Heat & Thermodynamics › Temperature and Thermal Expansion

A pendulum clock with a steel rod keeps correct time at $20\ ^\circ\text{C}$ . How many seconds does it lose in a day at $40\ ^\circ\text{C}$ ? ( $\alpha = 1.2 \times 10^{-5}\ \text{K}^{-1}$ ; $T \propto \sqrt{L}$ .)

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