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A particle starts from rest at x = 0 and moves along… | StemPy Lab
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A particle starts from rest at x = 0 and moves along the x-axis so that its velocity at position x is v = 4√x, with v in m/s and x in metres. Its acceleration, and the distance it covers in the first 2 s, are
Physics
Hard
High School (11–12)
Mechanics › Motion in a Straight Line
JEE Main
Created by
StemPy Lab
A particle starts from rest at
x
=
0
x = 0
x
=
0
and moves along the x-axis so that its velocity at position
x
x
x
is
v
=
4
x
v = 4\sqrt{x}
v
=
4
x
, with
v
v
v
in m/s and
x
x
x
in metres. Its acceleration, and the distance it covers in the first
2
s
2\ \text{s}
2
s
, are
8
m/s
2
8\ \text{m/s}^2
8
m/s
2
and
32
m
32\ \text{m}
32
m
16
m/s
2
16\ \text{m/s}^2
16
m/s
2
and
32
m
32\ \text{m}
32
m
4
m/s
2
4\ \text{m/s}^2
4
m/s
2
and
8
m
8\ \text{m}
8
m
8
m/s
2
8\ \text{m/s}^2
8
m/s
2
and
16
m
16\ \text{m}
16
m
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← The velocity of a particle changes with time as v = at + b/(t + c), where a, b and c are constants. The dimensions of a, b and c are
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Mechanics › Motion in a Straight Line
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