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A green solid of formula CrBr₃· 6H₂O is dissolved in… | StemPy Lab
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A green solid of formula CrBr₃· 6H₂O is dissolved in cold water. Excess silver nitrate gives 0.0300 mol of silver bromide from 0.0300 mol of the solid. Which is its structure?
Chemistry
Medium
High School (11–12)
Coordination Compounds › Isomerism in Coordination Compounds
A-Level
IB
Created by
StemPy Lab
A green solid of formula
CrBr
3
⋅
6
H
2
O
\text{CrBr}_{3}\cdot 6\text{H}_{2}\text{O}
CrBr
3
⋅
6
H
2
O
is dissolved in cold water. Excess silver nitrate gives
0.0300
mol
0.0300\ \text{mol}
0.0300
mol
of silver bromide from
0.0300
mol
0.0300\ \text{mol}
0.0300
mol
of the solid. Which is its structure?
[
CrBr
3
(
H
2
O
)
3
]
⋅
3
H
2
O
[\text{CrBr}_{3}(\text{H}_{2}\text{O})_{3}]\cdot 3\text{H}_{2}\text{O}
[
CrBr
3
(
H
2
O
)
3
]
⋅
3
H
2
O
[
CrBr
(
H
2
O
)
5
]
Br
2
⋅
H
2
O
[\text{CrBr}(\text{H}_{2}\text{O})_{5}]\text{Br}_{2}\cdot \text{H}_{2}\text{O}
[
CrBr
(
H
2
O
)
5
]
Br
2
⋅
H
2
O
[
CrBr
2
(
H
2
O
)
4
]
Br
⋅
2
H
2
O
[\text{CrBr}_{2}(\text{H}_{2}\text{O})_{4}]\text{Br}\cdot 2\text{H}_{2}\text{O}
[
CrBr
2
(
H
2
O
)
4
]
Br
⋅
2
H
2
O
[
Cr
(
H
2
O
)
6
]
Br
3
[\text{Cr}(\text{H}_{2}\text{O})_{6}]\text{Br}_{3}
[
Cr
(
H
2
O
)
6
]
Br
3
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