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A gas is at 2.0 × 10⁴ Pa and 340 K. Its molecules have… | StemPy Lab
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A gas is at 2.0 × 10⁴ Pa and 340 K. Its molecules have a diameter of 3.0 × 10⁻¹⁰ m. What is the mean free path? (kB = 1.38 × 10⁻²³ J/K)
Physics
Hard
High School (11–12)
Heat & Thermodynamics › Kinetic Theory of Gases
NEET
Created by
StemPy Lab
A gas is at
2.0
×
10
4
Pa
2.0 \times 10^4\ \text{Pa}
2.0
×
1
0
4
Pa
and
340
K
340\ \text{K}
340
K
. Its molecules have a diameter of
3.0
×
10
−
10
m
3.0 \times 10^{-10}\ \text{m}
3.0
×
1
0
−
10
m
. What is the mean free path? (
k
B
=
1.38
×
10
−
23
J/K
k_B = 1.38 \times 10^{-23}\ \text{J/K}
k
B
=
1.38
×
1
0
−
23
J/K
)
2.35
μ
m
2.35\ \mu\text{m}
2.35
μ
m
1.17
μ
m
1.17\ \mu\text{m}
1.17
μ
m
0.83
μ
m
0.83\ \mu\text{m}
0.83
μ
m
0.59
μ
m
0.59\ \mu\text{m}
0.59
μ
m
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