A 4.0 kg4.0\ \text{kg}4.0 kg block rests on a slope of 37∘37^\circ37∘ (sin37∘=0.6\sin 37^\circ = 0.6sin37∘=0.6, cos37∘=0.8\cos 37^\circ = 0.8cos37∘=0.8). What normal reaction does the slope give? Take g=10 m/s2g = 10\ \text{m/s}^2g=10 m/s2.
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