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7.5 g of solute X, molar mass 60 g/mol, is dissolved in… | StemPy Lab
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7.5 g of solute X, molar mass 60 g/mol, is dissolved in 90 g of water. 7.5 g of solute Y, molar mass 180 g/mol, is dissolved in another 90 g of water at the same temperature. Neither solute evaporates. Which statement is correct?
Chemistry
Hard
High School (11–12)
Solutions › Solubility, Vapour Pressure and Raoult's Law
JEE Main
AP
Created by
StemPy Lab
7.5
g
7.5\ \text{g}
7.5
g
of solute X, molar mass
60
g/mol
60\ \text{g/mol}
60
g/mol
, is dissolved in
90
g
90\ \text{g}
90
g
of water.
7.5
g
7.5\ \text{g}
7.5
g
of solute Y, molar mass
180
g/mol
180\ \text{g/mol}
180
g/mol
, is dissolved in another
90
g
90\ \text{g}
90
g
of water at the same temperature. Neither solute evaporates. Which statement is correct?
X lowers the vapour pressure of its water about three times as much as Y does
The two solutions have the same vapour pressure, because the masses are equal
X lowers the vapour pressure of its water about nine times as much as Y does
Y lowers the vapour pressure of its water about three times as much as X does
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← Statement I: A pair of liquids with a large positive deviation from Raoult's law can form a minimum-boiling azeotrope. Statement II: A positive deviation means a higher vapour pressure than Raoult's law, so the mixture boils at a lower temperature. Which choice is correct?
A solution of liquids A and B has a mole fraction of A of 0.45, and its measured vapour pressure is 19.0 kPa. Raoult's law would be worked out from the pure pressures, 32 kPa for A and 12 kPa for B. By what percentage is the measured value off from that calculation? →
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Solutions › Solubility, Vapour Pressure and Raoult's Law
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