Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
Write the structural formula of each, showing every bond to carbon.
Stem for the carbons in the chain: meth 1, eth 2, prop 3, but 4, pent 5, hex 6. Ending for the group: -ane, -ene, -yne, -ol (alcohol, ), -al (aldehyde, ), -one (ketone, C=O inside), -oic acid (). Prefix for a halogen: chloro, bromo.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. (a) . The last carbon has a double bond to one oxygen and a single bond to the .
Step 2. (b) .
Step 3. (c) : the second carbon has a hydrogen and a double bond to oxygen.
Check. Count four bonds on every carbon.
Answer: as drawn in steps 1 to 3.
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