A 60 W bulb and a 1000 W heater are both on a 220 V house supply…

Step 1. The bulb. $I = \dfrac{60\ \text{W}}{220\ \text{V}} = 0.273\ \text{A}$.

Step 2. The heater. $I = \dfrac{1000\ \text{W}}{220\ \text{V}} = 4.55\ \text{A}$.

Step 3. Total. $0.273\ \text{A} + 4.55\ \text{A} = 4.82\ \text{A}$.

Step 4. Reasons. Each appliance gets the full $220\ \text{V}$; each has its own switch; and if one fails, the others keep working.