What volume of 0.10 M sulphuric acid neutralises 36 mL of 0.15 M sodium hydroxide?
Contributed by StemPy LabTry it on paper first. A hint, the key idea and the worked solution are here when you need them.
What volume of sulphuric acid neutralises of sodium hydroxide? .
Need a reminder? The key ideaShow
Moles = concentration (M) × volume (L); millimoles = M × mL. At neutralisation the moles of equal the moles of . For a one to one reaction, ; otherwise use the ratio from the equation.
The worked solution
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. Base. .
Step 2. Acid. .
Step 3. Volume. .
Answer: .
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