Two signals are compared, and the gap between them is x - y…

Step 1. Substitute. $\dfrac{dv}{dx} = 1 - v^2$. At the start $v = 0$.

Step 2. Separate. $\displaystyle\int \dfrac{dv}{1 - v^2} = \int dx$, so $\tanh^{-1}v = x + C$. At $x = 0$, $v = 0$, so $C = 0$ and $v = \tanh x$.

Step 3. Return to $y$. $y = x - \tanh x$.

Step 4. Evaluate. At $x = 1$: $y = 1 - 0.76159 = 0.2384$. At $x = 2$: $y = 2 - 0.96403 = 1.0360$.