Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
Two meadows each have plants of four species. In meadow M the counts are , , and . In meadow N the counts are , , and .
Genetic diversity is the variety inside one species. Species diversity is the variety of species in a region. Ecological diversity is the variety of ecosystems. Simpson's index of diversity is , where is the count of one species and is the count of all (not in the NEET syllabus).
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. (a) Both have four species. The richness is equal.
Step 2. (b) Meadow M: the shares are , , and . The squares are , , and , which add to . So .
Step 3. Meadow N: four shares of give . So .
Step 4. (c) The richness is equal, but the evenness is not. In meadow M one species has per cent of the plants, so the meadow is much less diverse.
Answer: (a) equal; (b) and ; (c) the student counted the richness only and left out the evenness.
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