Two dice are rolled. Find the probability that at least one of them shows a number greater than 4.

List the outcomes in order: two coins give $4$ (HH, HT, TH, TT), three coins $8$, and two dice $36$ pairs (red, blue). Then $P(E) = \dfrac{\text{favourable outcomes}}{\text{all outcomes}}$. For "at least one", use $P(E) = 1 - P(\text{not } E)$.