Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
Two AC sources of the same frequency are joined in series. Their peak voltages are V and V, and the second is ahead of the first. Find the peak value of the total voltage, its rms value and its phase compared with the first source.
A phasor turns at . Its length is the peak value, and the angle between two phasors is the phase difference . A phase is a time delay . Voltages in series add as arrows, tip to tail. The reactances are and .
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Given. V along the axis. V at .
Plan. Add the arrows by their parts along and across the axis.
Step 1. The parts of the second arrow. Along the axis: V. Across the axis: V.
Step 2. The parts of the total. Along the axis: V. Across the axis: V.
Step 3. The peak value. V.
Step 4. The rms value. V.
Step 5. The phase. , so ahead of the first source.
Answer: V, V and .
Check. The sum of the peaks is V, and the total is a little less, because the peaks do not come together. The angle of lies between and , as it should. It fits.
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