Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
Three species were studied in the field.
Species A lives where the temperature goes from to during the year. Species B lives only in a hot spring where the temperature is between and . Fish C was found in water of salinity from to parts per thousand. Fish D was found only in water of salinity to parts per thousand.
Salinity is in parts per thousand, which is the grams of salt in each kilogram of water. Inland waters are below , the sea is to and some hypersaline lagoons are above . The air temperature falls about for each kilometre of height. A eurythermal organism bears a wide range of temperature, and a stenothermal one a narrow range.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. (a) Species A bears of range, so it is eurythermal. Species B lives in of range, so it is stenothermal.
Step 2. (b) Fish C bears parts per thousand of range, so it is euryhaline. Fish D lives only in fresh water, so it is stenohaline.
Step 3. (c) Fish C. It can bear both the river and the sea. Fish D would have an osmotic problem in the sea.
Step 4. (d) Thermal springs and deep sea hydrothermal vents. The spring of species B is below , so it is one of the cooler ones.
Answer: (a) A eurythermal, B stenothermal; (b) C euryhaline, D stenohaline; (c) C; (d) thermal springs and deep sea hydrothermal vents.
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