Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
Three plants are found in a garden. Plant X has root nodules and a flower with a standard, wings and a keel, and its fruit is a pod. Plant Y has an underground stem tuber, five joined petals and a berry. Plant Z has a bulb, long leaves with parallel veins and six similar petal-like parts. Name the family of each.
Fabaceae: zygomorphic flower, papilionaceous corolla (standard, two wings, a keel of two joined petals), ten stamens with nine joined and one free, one carpel, a legume, root nodules. Solanaceae: radial flower, united sepals and petals, five epipetalous stamens, two joined carpels, a berry or a capsule. Liliaceae: a monocot, six tepals in two whorls, six epiphyllous stamens, three joined carpels, a capsule.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. Plant X. Root nodules, a papilionaceous corolla and a legume mark Fabaceae.
Step 2. Plant Y. A stem tuber, joined petals and a berry mark Solanaceae.
Step 3. Plant Z. A bulb, parallel veins and six tepals mark Liliaceae, a monocot.
Answer: X is in Fabaceae, Y in Solanaceae and Z in Liliaceae.
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