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Three coins are tossed together. Find the probability of getting exactly two heads…

Try it on paper first. A hint, the key idea and the worked solution are here when you need them.

Three coins are tossed together. Find the probability of getting exactly two heads. Give the number of outcomes in all, the number with exactly two heads, and the probability as a decimal.

Need a reminder? The key ideaShow

List the outcomes in order: two coins give $4$ (HH, HT, TH, TT), three coins $8$ , and two dice $36$ pairs (red, blue). Then $P(E) = \dfrac{\text{favourable outcomes}}{\text{all outcomes}}$ . For "at least one", use $P(E) = 1 - P(\text{not } E)$ .

The worked solution

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Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.

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