Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
Three circular fountains have the edges , and , with lengths in metres. A guard stands at the point from which the tangent lengths to the three fountains are equal. Find the coordinates of that point and the length of each tangent.
The radical axis of and is , and the tangent lengths from any point of it are equal. The radical centre of three circles is the point where their three radical axes meet. Circles are orthogonal when .
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. Two radical axes. The first minus the second gives , which is . The first minus the third gives , which is .
Step 2. The meeting point. Adding and gives , so and . This is the radical centre. It also lies on the third radical axis, because is , which is at .
Step 3. The tangent length. . So the length is metres. The other two circles give and .
Answer: the point is and each tangent is metres long.
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