Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
The strength of bleaching powder is given as the percentage of available chlorine, which is the mass of chlorine that releases the same amount of iodine from iodide as the sample does. A sample of of bleaching powder is made up to of solution. A volume of of the solution is added to an excess of acidified potassium iodide. The reactions are and . The liberated iodine needs of sodium thiosulphate. One mole of chlorine liberates one mole of iodine, and its molar mass is . Find the iodine in the portion, the chlorine equivalent of the whole sample and the percentage of available chlorine.
Redox: electrons lost equal electrons gained. In iodometry, 2 mol of thiosulphate react with 1 mol of iodine. In a disproportionation one species forms two products with higher and lower oxidation states. In a puzzle, follow the clues one at a time: gas tests, colours and the reagents of the standard conversions. At 273 K and 1 atm, 1 mol of gas fills 22.4 L.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Plan. Thiosulphate gives iodine, iodine gives chlorine, and the portion is scaled up to the whole.
Step 1. Thiosulphate. .
Step 2. Iodine in the portion. Two thiosulphate ions for each iodine: .
Step 3. The whole sample. The portion is of the solution, so the whole sample gave of iodine.
Step 4. Chlorine equivalent. .
Step 5. The percentage. .
Answer: , and .
Check. The answer is below and close to the usual range for bleaching powder.
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