Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
The point lies on the graph of . The point lies on the graph of . Find and in radians, and find . Explain why comes out as a simple number.
The domain of and is . The graph of an inverse is the reflection of the original in . and for , and has the range .
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. The value of . .
Step 2. The value of . .
Step 3. The sum. A right triangle with sides has an angle with sine and cosine . So . Then and .
Answer: , and , because the angle whose cosine is is the same angle whose sine is .
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