MediumChemistryHigh School (11–12)Structure of the Atom › Light, Atomic Spectra and the Bohr ModelNumericalNEET Board Exam

Find the shortest wavelength of the Brackett series, which ends on n₁ = 4, and the energy of a…

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Try it on paper first. A hint, the key idea and the worked solution are here when you need them.

Find the shortest wavelength of the Brackett series, which ends on $n_1 = 4$ , and the energy of a photon of this wavelength in eV. In which part of the spectrum is it? What do you notice about the energy?

Need a reminder? The key ideaShow

Hydrogen's lines obey $\tilde{\nu} = R_H\left(\dfrac{1}{n_1^2} - \dfrac{1}{n_2^2}\right)$ , with $R_H = 1.097 \times 10^{7}\ \text{m}^{-1}$ . Lyman ends on $n_1 = 1$ , Balmer on $2$ , Paschen on $3$ , Brackett on $4$ . From level $n$ , $\dfrac{n(n - 1)}{2}$ different lines are possible.

The worked solution

Have you tried it?

Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.

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