A concave mirror has a focal length of 14 cm…

Step 1. $u = -56\ \text{cm}$. $\dfrac{1}{v} = -\dfrac{1}{14\ \text{cm}} + \dfrac{1}{56\ \text{cm}} = -\dfrac{3}{56\ \text{cm}}$, so $v = -18.7\ \text{cm}$ and $m = -0.33$. Real, inverted, smaller.

Step 2. $u = -28\ \text{cm}$. The object is at $C$: $v = -28\ \text{cm}$ and $m = -1$. Real, inverted, the same size.

Step 3. $u = -21\ \text{cm}$. $\dfrac{1}{v} = -\dfrac{1}{14\ \text{cm}} + \dfrac{1}{21\ \text{cm}} = -\dfrac{1}{42\ \text{cm}}$, so $v = -42\ \text{cm}$ and $m = -2$. Real, inverted, larger.

Step 4. $u = -10.5\ \text{cm}$. $\dfrac{1}{v} = -\dfrac{1}{14\ \text{cm}} + \dfrac{1}{10.5\ \text{cm}} = \dfrac{1}{42\ \text{cm}}$, so $v = +42\ \text{cm}$ and $m = +4$. Virtual, upright, larger.

What do we see? As the object comes closer, the real image moves out and grows. Inside the focus, it jumps behind the mirror.