The diagonals AC and BD of a cyclic quadrilateral ABCD are drawn…

Step 1. The angle CBD. Both $\angle CAD$ and $\angle CBD$ are on the chord $CD$. So $\angle CBD = 46^\circ$.

Step 2. The angle ABC. $\angle ABC = 52^\circ + 46^\circ = 98^\circ$.

Step 3. The angle ADC. It is opposite to $\angle ABC$. So $\angle ADC = 180^\circ - 98^\circ = 82^\circ$.

Step 4. The angle ACD. In the triangle $ACD$, $\angle ACD = 180^\circ - 82^\circ - 46^\circ = 52^\circ$.