Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
The complex is octahedral with . The atomic number of nickel is 28. Write the electron arrangement of as the numbers of electrons in the and sets. Then find the CFSE in units of and in kJ/mol.
In an octahedral field the set lies at and the set at . A d electron count of 4 to 7 gives high spin if and low spin if . In a tetrahedral field the set lies at and the set at , with . in an octahedron.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. The electrons. is . The set holds six electrons and the set holds two, in any field. So and .
Step 2. In units of . .
Step 3. In kJ/mol. .
Answer: , which is .
Check. The sign is negative, so the ion is more stable than in the free state.
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