The charge of one proton is 1.6 × 10⁻¹⁹ C…

Step 1. (a) $11 \times 1.6 \times 10^{-19}\ \text{C} = 17.6 \times 10^{-19}\ \text{C} = 1.76 \times 10^{-18}\ \text{C}$.

Step 2. (b) The $11$ electrons carry $-1.76 \times 10^{-18}\ \text{C}$.

Step 3. (c) $1.76 \times 10^{-18}\ \text{C} - 1.76 \times 10^{-18}\ \text{C} = 0\ \text{C}$. The atom is neutral.