A 950 kg car moves at 18 m/s. Its brakes give a steady force of 5700 N against the motion.

Step 1. Kinetic energy. $\tfrac12 \times 950\ \text{kg} \times (18\ \text{m/s})^2 = 153\,900\ \text{J}$.

Step 2. Distance. $d = \dfrac{153\,900\ \text{J}}{5700\ \text{N}} = 27.0\ \text{m}$.

Step 3. Twice the speed. Four times the energy, so four times the distance: $108\ \text{m}$.