Show that Bernoulli's equation gives the pressure in a liquid at rest…

Step 1. With $v = 0$: $p_1 + \rho gh_1 = p_2 + \rho gh_2$, so $p_2 - p_1 = \rho g(h_1 - h_2)$.

Step 2. For the surface ($p_1 = p_0$) and a point $h$ below: $p = p_0 + \rho gh$, the law of the first course.

Step 3. Numbers. $1000\ \text{kg/m}^3 \times 9.8\ \text{m/s}^2 \times 3.0\ \text{m} = 29\,400\ \text{Pa}$.