Red-green colour vision loss is X-linked and recessive…

Allele frequency. The affected males are $q = 0.06$, so $p = 0.94$.

(a) $q^2 = 0.0036$, so $0.0036 \times 10000 = 36.0$ females.

(b) $2pq = 2 \times 0.94 \times 0.06 = 0.1128$.

(c) The son takes one X chromosome of his mother at random, and a random X chromosome carries the allele with probability $q$. So the probability is $0.0600$. (Adding $q^2 \times 1 + 2pq \times \tfrac{1}{2}$ gives the same value.)

(d) $q^2 / q = q$, so $6.0$ affected females for every $100$ affected males.

(e) Among healthy women the carrier share is $0.1128 / (1 - 0.0036) = 0.1132$. A carrier mother passes on the allele to a son with probability $\tfrac{1}{2}$, so the probability is $0.0566$. The father does not matter for a son, because a son gets his X chromosome from his mother.