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  1. Problems
  2. /Potash alum is KAl(SO₄)₂· 12H₂O with a molar mass of 474.37 g/mol…
EasyChemistryHigh School (11–12)The p-Block Elements › Groups 13 and 14: Boron and Carbon FamiliesNumericalA-LevelIB

Potash alum is KAl(SO₄)₂· 12H₂O with a molar mass of 474.37 g/mol…

StemPy LabContributed by StemPy Lab

Try it on paper first. A hint, the key idea and the worked solution are here when you need them.

Potash alum is KAl(SO4)2⋅12H2O\text{KAl}(\text{SO}_{4})_{2}\cdot 12\text{H}_{2}\text{O}KAl(SO4​)2​⋅12H2​O with a molar mass of 474.37 g/mol474.37\ \text{g/mol}474.37 g/mol. Take the molar mass of water as 18.015 g/mol18.015\ \text{g/mol}18.015 g/mol and of aluminium as 26.98 g/mol26.98\ \text{g/mol}26.98 g/mol. Find the percentage of water of crystallisation, the percentage of aluminium and the mass of alum that holds 1.00 g1.00\ \text{g}1.00 g of aluminium.

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Need a reminder? The key ideaShowHide

Faraday's law for aluminium: m=M Q3Fm = \dfrac{M\,Q}{3F}m=3FMQ​ with Q=ItQ = ItQ=It. Energy in kilowatt hours is V Q3.6×106\dfrac{V\,Q}{3.6 \times 10^6}3.6×106VQ​. Thermite: 2Al+Fe2O3→Al2O3+2Fe2\text{Al} + \text{Fe}_{2}\text{O}_{3} \to \text{Al}_{2}\text{O}_{3} + 2\text{Fe}2Al+Fe2​O3​→Al2​O3​+2Fe gives out 851.5 kJ851.5\ \text{kJ}851.5 kJ for 2 mol of Al. A hydrate has its water in the molar mass.

The worked solution

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Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.

Step 1. Water. 12×18.015=216.18 g/mol12 \times 18.015 = 216.18\ \text{g/mol}12×18.015=216.18 g/mol, so the percentage is 216.18/474.37×100=45.6%216.18 / 474.37 \times 100 = 45.6\%216.18/474.37×100=45.6%.

Step 2. Aluminium. 26.98/474.37×100=5.69%26.98 / 474.37 \times 100 = 5.69\%26.98/474.37×100=5.69%.

Step 3. Alum for 1.00 g1.00\ \text{g}1.00 g of aluminium. 1.00/0.0569=17.6 g1.00 / 0.0569 = 17.6\ \text{g}1.00/0.0569=17.6 g.

Answer: 45.6%45.6\%45.6% water, 5.69%5.69\%5.69% aluminium, and 17.6 g17.6\ \text{g}17.6 g of alum.

Check. The molar mass ratio 474.37/26.98=17.6474.37 / 26.98 = 17.6474.37/26.98=17.6 gives the same answer.

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  1. Aluminium and its compoundsThe Boron Family: Boron, Borax and Aluminium

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