Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
Magnesium silicide () of mass reacts with excess hydrochloric acid and forms only silane: . The silane is then burned in oxygen: . Take at and , and for silica. Find the volume of silane, the volume of oxygen that burns it and the mass of silica.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. Moles. of MgSi.
Step 2. Silane. The same number of moles: .
Step 3. Oxygen. .
Step 4. Silica. One mole of SiO for each mole of silane: .
Answer: , and .
Watch out. In practice the reaction gives a mixture of silanes, and only about a quarter of the silicon ends as . This problem takes the ideal case.
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Each Cl of a chloride that is hydrolysed ends as one HCl, and HCl is a strong acid, so equals the moles of HCl for each litre. A gas at and has a molar volume of . Magnesium silicide and acid give silane, . Lithium aluminium hydride and water give four moles of hydrogen for each mole.