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For this dictionary, write the expression for each answer.
Contributed by StemPy LabTry it on paper first. A hint, the key idea and the worked solution are here when you need them.
For this dictionary, write the expression for each answer.
- the teacher of class 7B
- the second mark of class 7A
- the average mark of class 7B
- a new class 7C with the teacher Ms Das and the marks 70 and 85
The worked solution
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Plan. Read each expression from left to right, one key at a time.
school["7B"]["teacher"]gives"Mr Khan".school["7A"]["marks"][1]gives75. The first positions start at 0, so the second mark is position 1.sum(school["7B"]["marks"]) / len(school["7B"]["marks"])gives67.5, which is 135 divided by 2.school["7C"] = {"teacher": "Ms Das", "marks": [70, 85]}adds the new record.
Check. Run the lines in a program, and print school at the end to see the new class.
Answer: "Mr Khan", 75, 67.5, and the new record as in line 4.
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