Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
Liquids A and B form an ideal solution at . Pure A has a vapour pressure of and pure B has . A solution has a mole fraction of A of . Find the partial pressure of each liquid, the total pressure and the mole fraction of A in the vapour.
For two volatile liquids, Raoult's law gives each partial pressure as , and the total pressure is the sum, . The vapour has . For a non-volatile solute, and . Mole fractions use moles, so divide each mass by its molar mass first.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Given. , , , so .
Plan. Raoult's law for each liquid, then add, then divide.
Step 1. Partial pressures. . .
Step 2. Total. .
Step 3. The vapour. .
Answer: , , and .
Check. The total lies between and . The vapour holds less A than half, although A is the more volatile liquid, because the liquid is only 30 % A.
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