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Lead(IV) oxide reacts with concentrated hydrochloric acid and gives chlorine: PbO₂ + 4HCl → PbCl₂ +…
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Lead(IV) oxide reacts with concentrated hydrochloric acid and gives chlorine: . The standard potential of PbO changing to Pb in acid is and that of Cl changing to Cl is . The reaction transfers 2 electrons. Find the standard cell potential, the energy released for each mole of reaction, and the mass of chlorine () that forms from of lead(IV) oxide ().
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The worked solution
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Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. Cell potential. .
Step 2. Energy released. .
Step 3. Moles of oxide. .
Step 4. Chlorine. The same number of moles forms: .
Answer: , and .
Check. The standard potential is only slightly positive, so the reaction needs concentrated acid. A high concentration of H and Cl pushes it to the right, and the chlorine escapes as a gas. This is why the oxide gives chlorine only with the concentrated acid.
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