Iodobenzene is made from nitrobenzene in three steps…

Iodobenzene is made from nitrobenzene in three steps. A chemist chooses this route because direct iodination of benzene works badly, and wants to know how much of each material to weigh out. Assume that every reagent other than those named is in large excess. First, tin and hydrochloric acid reduce $24.6\ \text{g}$ of nitrobenzene ($123\ \text{g/mol}$) to aniline in a yield of $90\ \%$. Second, the aniline is diazotised in the cold in a yield of $95\ \%$. Third, potassium iodide ($166\ \text{g/mol}$) is added to the diazonium salt, and iodobenzene ($204\ \text{g/mol}$) forms in a yield of $80\ \%$. Direct iodination of benzene is not a good route, because iodine alone is too weak an electrophile. Find the amount of aniline formed, the amount of diazonium salt formed and the mass of iodobenzene collected. Then find the least mass of potassium iodide needed for the diazonium salt formed.