Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
In the half-deflection method, a galvanometer is joined in series with a cell of V and a resistance box of . The deflection is divisions, which is the full scale. A shunt of across the galvanometer makes the deflection divisions. Find the resistance of the galvanometer, the current for full deflection, and the figure of merit, the current per division.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. The resistance. .
Step 2. The full-scale current. .
Step 3. The figure of merit. per division.
Answer: , A and A per division.
Check. is a little larger than . The relative difference is , small, because is much larger than .
Log in to join the discussion.
Loading…
Half deflection: . Ammeter: , and its resistance is . Voltmeter: , and its resistance is . For a diode, the dynamic resistance is , and the knee voltage is where the straight part of the characteristic meets the voltage axis.