Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
In the Carius method, 0.1160 g of an organic compound that contains sulphur is heated with fuming nitric acid in a sealed tube. The sulphur becomes sulphuric acid. Barium chloride then gives a precipitate of barium sulphate, (), with a mass of 0.2330 g. Use S = 32 in g/mol. Find the amount of barium sulphate, the mass of sulphur, the percentage of sulphur, and the molar mass of the compound if each molecule holds one sulphur atom.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. .
Step 2. .
Step 3. .
Step 4. One sulphur atom in a molecule: .
Answer: , , and .
Check. The 0.1160 g of compound is of molecules, so the molar mass is .
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After a sodium fusion, sulphur is and a halogen is . Silver nitrate gives AgCl (white, soluble in dilute ammonia solution), AgBr (pale yellow, sparingly soluble) or AgI (yellow, insoluble). The mass of halogen in a precipitate is the mass of the precipitate times .