Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
In a repeat of Hertz's experiment, a metal sheet reflects a wave and makes standing waves. A detector finds that the places of no field are m apart. Use m/s. Find (a) the wavelength, (b) the frequency of the transmitter and (c) the length of a half-wave antenna for this frequency. (d) The transmitter is changed to make its frequency times larger, with the same amplitude of oscillation of the charge. By what factor does the radiated power change?
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. The wavelength. Neighbouring nodes are apart, so .
Step 2. The frequency. .
Step 3. The antenna. A half-wave antenna is m long, the same as the distance between the nodes.
Step 4. The power. The power is in proportion to , hence to . The factor is .
Answer: m; MHz; m; times.
Check. A wavelength of m is small enough to build the whole experiment on a laboratory bench. Hertz used waves of this kind.
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A plane electromagnetic wave is transverse, with , in phase, travelling along . In vacuum and . In a material is unchanged, and . An accelerated charge radiates.