Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
In a plant, two genes lie so close together on one chromosome that crossing over never separates them. A plant is heterozygous for these two genes, with A and B on one chromosome and a and b on the other. It pollinates itself, and F2 plants grow. A and B are dominant.
For comparison, the genes on different chromosomes would give , , and .
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Given. AB over ab, no crossing over, F2 plants.
Plan. Find the gametes that the plant can make. Then pair them.
Step 1. Gametes. With no crossing over, the plant makes only the parental gametes AB and ab, half each.
Step 2. The square. Pairing gives AB with AB (AABB), AB with ab (AaBb, twice) and ab with ab (aabb). So three boxes are AB and one box is ab.
Step 3. (a) Both dominant: plants.
Step 4. (b) Kinds like Aabb or aaBb need a recombinant gamete, which cannot form: plants.
Step 5. (c) Both recessive: plants.
Answer: plants; plants; plants.
Check. . The ratio is , and that is a monohybrid ratio, as if there were only one gene.
Watch out. Complete linkage is rare. In real crosses a few recombinants usually appear.
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Linked genes lie on the same chromosome. In a test cross of a double heterozygote with a double recessive, the recombinant offspring are the small classes. The recombination frequency is the number of recombinants divided by all the offspring, in per cent, and one per cent is one map unit. Of three linked genes, the two that are farthest apart are the end genes.
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