Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
In a laboratory, a laser beam is split into two beams by a thin glass plate. The two beams are sent along different paths and made to cross on a screen. Because they come from the same laser, they are coherent. One path loses more light than the other, so the two beams reach the screen with unequal strength. Each beam alone would light the screen with an intensity of and . Together they make a pattern of bright and dark places. The student has measured the strength of each beam with a light meter. She wants to know how clear the dark places of the pattern will be. She also wants to know how unequal two beams may be if the brightest place is to be a great many times as bright as the darkest. Find the greatest and the least intensity in the pattern, and the intensity where the phase difference is . Find the visibility of the fringes, which is . Then find the ratio of the intensities of two beams for which .
Two coherent waves of phase difference give . A path difference gives . Bright: . Dark: .
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. The amplitudes. In arbitrary units and .
Step 2. The greatest intensity. .
Step 3. The least intensity. .
Step 4. At . , so .
Step 5. The visibility. .
Step 6. The beams for 49. . So , and , giving . The intensity ratio is .
Answer: ; ; ; ; (that is ).
Watch out. The ratio of the amplitudes is not the ratio and not the ratio of the intensities. A mild difference of intensity, , already makes a ratio of between the brightest and the darkest.
Log in to join the discussion.
Loading…