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  1. Problems
  2. /A jar holds 380 g of brine that is 9 % salt by mass…
MediumChemistryHigh School (9–10)GeneralMixtures and Solutions › Mixtures, Solutions and ColloidsNumericalBoard Exam

A jar holds 380 g of brine that is 9 % salt by mass…

StemPy LabContributed by StemPy Lab

Try it on paper first. A hint, the key idea and the worked solution are here when you need them.

A jar holds 380 g380\ \text{g}380 g of brine that is 9 %9\ \%9 % salt by mass. How many grams of salt and how many grams of water does it hold?

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Work it out on paper, then type your number. The answer itself stays hidden.

g
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Need a reminder? The key ideaShowHide

Mass by mass %=mass of solutemass of solution×100\% = \dfrac{\text{mass of solute}}{\text{mass of solution}} \times 100%=mass of solutionmass of solute​×100, where the solution is solute plus solvent. Volume by volume %=volume of solutevolume of solution×100\% = \dfrac{\text{volume of solute}}{\text{volume of solution}} \times 100%=volume of solutionvolume of solute​×100.

The worked solution

Have you tried it?

Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.

Step 1. The salt. 9100×380 g=34.2 g\dfrac{9}{100} \times 380\ \text{g} = 34.2\ \text{g}1009​×380 g=34.2 g.

Step 2. The water. 380 g−34.2 g=345.8 g380\ \text{g} - 34.2\ \text{g} = 345.8\ \text{g}380 g−34.2 g=345.8 g.

Answer: 34.2 g34.2\ \text{g}34.2 g of salt and 345.8 g345.8\ \text{g}345.8 g of water.

Check. 34.2 g380 g×100=9 %\dfrac{34.2\ \text{g}}{380\ \text{g}} \times 100 = 9\ \%380 g34.2 g​×100=9 %.

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  1. Solutions and their concentrationMixtures, Solutions and Colloids

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