Water rises in a very thin tube by capillary action, h = 2T/(ρ g r)…

Step 1. The radius. $r = 8 \times 10^{-6}\ \text{m}$.

Step 2. The top and the bottom. $2T = 2 \times 0.0728\ \text{N/m} = 0.1456\ \text{N/m}$. For the bottom, $\rho g r = 1000\ \text{kg/m}^3 \times 9.8\ \text{m/s}^2$ $\times\ 8 \times 10^{-6}\ \text{m}$ $= 0.0784\ \text{N/m}^2$.

Step 3. The height. $h = \dfrac{0.1456\ \text{N/m}}{0.0784\ \text{N/m}^2} = 1.86\ \text{m}$.

Step 4. The tree. No: $1.86\ \text{m}$ is far less than $30\ \text{m}$. Transpiration from the leaves is the main pull.