HardChemistryHigh School (11–12)The d- and f-Block Elements › Transition Elements (d-Block)NumericalA-LevelIBJEE Main
Hot, acidified potassium permanganate oxidises toluene to benzoic acid: 5C₆H₅CH₃ + 6MnO₄⁻ + 18H⁺ →…
Contributed by StemPy LabTry it on paper first. A hint, the key idea and the worked solution are here when you need them.
Hot, acidified potassium permanganate oxidises toluene to benzoic acid: . A sample of of toluene, with a molar mass of , is oxidised completely. Benzoic acid has a molar mass of . Find the moles of toluene, the moles of permanganate needed and the mass of benzoic acid formed.
Need a reminder? The key ideaShow
Moles = mass in g divided by molar mass in g/mol, or concentration in mol/L times volume in litres. Take every mole ratio from the balanced equation, and follow the chain one step at a time.
The worked solution
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. Toluene. .
Step 2. Permanganate. .
Step 3. Benzoic acid. The ratio is , so . The mass is .
Answer: , and .
Check. Each toluene loses 6 electrons: carbon goes from to . That is . Each permanganate takes 5, and .
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