Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
Hot, acidified potassium permanganate oxidises toluene to benzoic acid: . A sample of of toluene, with a molar mass of , is oxidised completely. Benzoic acid has a molar mass of . Find the moles of toluene, the moles of permanganate needed and the mass of benzoic acid formed.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. Toluene. .
Step 2. Permanganate. .
Step 3. Benzoic acid. The ratio is , so . The mass is .
Answer: , and .
Check. Each toluene loses 6 electrons: carbon goes from to . That is . Each permanganate takes 5, and .
Log in to join the discussion.
Loading…
Moles = mass in g divided by molar mass in g/mol, or concentration in mol/L times volume in litres. Take every mole ratio from the balanced equation, and follow the chain one step at a time.